3n=[n*(n-3)]/2

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Solution for 3n=[n*(n-3)]/2 equation:


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7-((2/3)*x) = 0

15-((2/3)*x) < x-8

7-(i/6)-(9*i) = 0

2*(log(5)(20)) = 0

log(5)(0.5) = 0

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